A red LED on 5 V
(5 − 2) ÷ 0.02 = 150 Ω, a standard value; the resistor dissipates 0.06 W.
Find the series resistor for one or more LEDs, with the nearest standard value and power rating.
Enter your values and select Calculate to see the result.
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LEDs need a resistor in series to limit the current. Enter the supply voltage, the LED's forward voltage and the current you want (often 20 mA), and how many LEDs are in series. The calculator finds the exact resistance, the next standard E12 value up, the current that value gives and the power the resistor must handle.
R = (Vsupply − n × Vf) ÷ I
P = (Vsupply − n × Vf) × I
(5 − 2) ÷ 0.02 = 150 Ω, a standard value; the resistor dissipates 0.06 W.
(12 − 3.2) ÷ 0.02 = 440 Ω; the next E12 value is 470 Ω, giving about 18.72 mA.
A larger resistor gives slightly less current, which is safe; a smaller one could overdrive the LED.
It's better to give each parallel LED its own resistor — small differences make one LED hog the current.
At least the calculated power, ideally double it. ¼ W resistors suit most single-LED circuits.
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